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# 2017/2018 NECO GCE PHYSICS PRACTICAL QUESTION AND ANSWER NOW AVAILABLE

Posted by on October 25th, 2017

NO-1bii)
It’s because an iron ship is not completely solid. It has full of air filled in it. So the average density of the ship as a whole is less than the density of water. Therefore immersed portion of the ship displaces water equal to its weight. So the ship floats whereas a sheet of iron is compact and there are no air spaces inside it. Iron is denser than that of water. The weight of the sheet is greater than the weight of the water displaced by the sheet. So it sinks

………. Typing in progress

2aiv)
-I ensured tight connections
-I avoided error due to parallax when reading the voltmetre
-I ensured the key is opened after each reading to prevent the cell from running down

2bii) M=V/U
object height=8cm
Image height=192cm
M=192/8
M=24cm
=======================

2v)
SLOPE

Slope,s =y2-y1/x2-x1
=56.7-20/4-1
=36.7/3
=12.233
=12.23

2vi)

U = 100/S = 100/12.23
= 8.176
=8.18

2vii)

– I will avoid error due to parallax while reading the meter rule.

-I will ensure the mass is kept dried before weighing

=======================

: 3a)
1 | R(ohms) | R^-1(ohms)| L(cm) | L(cm)

1  | 1.00 | 1.000 | 13.50 | 0.074

2  | 2.00 | 0.500 | 27.50 | 0.036

3  | 3.00 | 0.333 | 41.50 | 0.024

4  | 4.00 | 0.250 | 55.00 | 0.018

5  | 5.00 | 0.200 | 69.00 | 0.014

*note* where u see ohms put the ohms sign

(3av)
Slope=Change in R^-1/Change in L^-1
=(0.500-0.200)/(0.036-0.018)
S=0.30/0.018
=16.67cm/n

3avi)
Rs=100/16.67
Rs=5.99880n/cm
Rs=6.0n/cm

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