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Neco 2019 Chemistry Obj & Essay Answer Now Available.


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How to Get 2019 NECO 2019 JUNE/JULY CHEMISTRY Question Paper.

Follow the steps below to get your Neco may/june chemistry questions and answers 1 hours before your exam time.

2019 NECO CHEMISTRY ANSWERS
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CHEMISTRY-OBJ!
1CEDEABCCEC
11ACDCBCDCAB
21EAECBCDBAC
31BBBACCBBDD
41ACDEEACBDB
51CCEBCBBCBD

 

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(4ai)
Sublimation is the process whereby a solid changes state directly to the gaseous state without passing through the liquid state upon heating

(4aii)
Iodine and Ammonium chloride

(4b)
(i) He may have conducted the experiment in a partial vacuum
(ii) Addition of impurities like salt
(iii) T°K = 78 +273 = 351K

(4ci)
(i)presence of moisture
(ii)presence of oxygen

(4cii)
4Al(NO3)3(s) ——> 2Al2O3(s) +3O2(q) + 12NO2(q)

(4ciii)
(i)sols and gels
(ii)Aerosols
(iii)Emulsion

(4d)
Using CAVA/CBVB =nA/nB

0.122*20.50/CB * 25.00 = 2/1
CB = 0.05002moles/dm^3

Using :
Gram conc = molar conc * molar mass
Molar mass of hydrated salt = 6.203 * 1/0.05002
=124g/mol

Now;
106 + (18x)= 124
18x = 124 – 106
18x = 18
x = 18/18 = 1
SaH was NaCO3. H2O

(4e)
(i)the metal is potassium
(ii) period 4
(iii)group 1
(iv)2k(s) + 2H2O —-> 2NaOH(aq) + H2(q)
=====================================

(3ai)
Chemical industry are companies that produce industrial chemicals

(3aii)
– Favourable climatic conditions
– It’s nearness to the source of raw materials
– The availability of space to store raw materials

(3b)
(i) It is aldose and it contains alkanal (-CHO) group
(ii) Brick red precipitate is formed
(iii) Reducing sugar possess a free aldehyde (-CHO) or ketone (-C=O) group while non reducing sugar a free aldehyde or ketone group is lacking

(3ci)
(i) Pollution is the release of unwanted materials into the environment which cause adverse change
(ii) Pollutant is a substance or energy introduced into the environment that has undesired effects or adversely effects the usefulness of a resource

(3cii)
(i)Plastic
(ii)Polythene
(iii)Pesticides

(3ciii)
VC2H2=?
MCaCa=3.2g
MCaCa=40+(2*12)
=40+24
=64glmol
n=m/m=3.2/64
n=0.05mole of CaC2
CaC2+2H2O —> Can(OH)2+C2H2
0.05mole of CaC2 —-> 0.05mole of C2H2 because the mole ratio are equal
NC2H2=0.05moles
n=V/VM
VC2H2=n*Vm = 0.05*22.4
VC2H2=1.12dm³

(3d)
(i)Na2CO3 —-> soluble
(ii)K2CO3 —-> soluble
(iii)ZnCO3 —-> insoluble
(iv)(NH4)2CO3 —-> soluble
=====================================

(2aii)
Avogadro’s law states that equal volumes of all gases under the same temperature and pressure contain the same number of molecules

(2aii)
no2=?

2SO2(g) + O2 —> 2SO3(g)

2 : 1 : 2

VSO2 = 7.50dm^3

nSO2 = V/Vm = 7.50/22.4 = 0.3348moles

2moles of SO2 —-> 1 moles of O2
0.3348 —-> x

x = 0.3348/2 = 0.1674moles

nO2 = 0.1674moles
np = n × L = 0.167 × 6.02 × 10^23
np = 1.008 × 10^23molecules
np = 1.01×10^23 molecules

(2bi)
(I) NaCl —–> Valency of chlorine is 1
(II) NaO2 —–> Valency of oxygen is 2
(III) Na3N ——> Valency of Nitrogen is 3

(2bii)
(i)Formation of black soap
(ii)Formation of glycerol
(iii)It helps in the precipitation of large biomolecules such as protein

(2ci)
(i)Na2O
(ii)MgO
(iii)CaO

(2cii)
Because they react with water to form acids

(2ciii)
– Reaction with sulphur
S(s) + O2(g) —> SO2(g)

– Reaction with metals
4Na(s) + O2(g) —-> 2NaO(s)

(2di)
Ion is any atom or group of atoms which possess an electric charge

(2dii)
TABULATE PLS
ION : H^+, F^-, N^3+

NUMBER OF PROTONS: 1,9,13

NUMBER OF NEUTRONS : 0, 10, 14

NUMBER OF ELECTRONS : 0, 10, 10

(2ei)
Monosaccharide are simple six carbon sugar having the formula C6H12O6 eg glucose and it’s isomers are fructose and galactose, both obtainable from fruits and honey

(2eii)
(i)fructose
(ii)galactose
=====================================

(1a)
Ammonium chloride —> sublimation
Ink —> chromatography
Iron filling —> magnetic separation

(1aii)
-Example Of physical Change
(i)change of matter
(ii)evaporation of sodium chloride

-Example of chemical change
(i)burning of firewood
(ii)rusting of iron

(1bi)
(i)they are good reducing agent
(ii)they form basic oxide
(iii)they formed electro valent bonding

(1bii)
Aluminum tetraoxosulphate(vi) is prepared by the action of hot concentrated tetraoxosulphate(vi)acid on aluminum oxide
Al2O3(s) + 3H2SO4(aq)—->Al2(SO4)3(aq)+3H2O(i)
Aluminum tetraoxosulphate(vi) is moderately soluble in water

(1ci)
Hydrogen

(1cii)
(i)it is denser than air
(ii)it is very poisonous

(1ciii)
Pb(NO3)2+H2S—->Pbs+2HNO3

(1civ)
It turn black due to the formation of black lead (II) sulphide

(1di)
Water gas contains flammable gases whereas the producer gas contains both flammable and non-flammable gases

(1dii)
(I) Diamond —> Octahedral in shape
(II) Graphite —> Hexagonal in shape

(1e)
(i) For manufacturing of ammonia and fertilizer
(ii) It is used as a refrigerant and also used to shrink metal parts
(iii) It is used in grinding substances that are too tough to grind at normal temperature
=====================================

COMPLETED!..

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