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Waec 2018 Physics Obj And Theory Answers – May/June


 

2018 WAEC PHYSICS THEORY ANSWERS 

PHYSICS OBJ:

1-10: CAABACBADB
11-20:ACCCDABDCC
21-30:DBADCABCAB
31-40:CCBBCCBABD
41-50:BDCDBABBDC

 

10a) Diffraction refers to various phenomena that occur when a wave encounters an obstacle or a slit. It is defined as the bending of light around the corners of an obstacle or aperture into the region of geometrical shadow of the obstacle.

10b)
Critical angle: the angle of incidence beyond which rays of light passing through a denser medium to the surface of a less dense medium are no longer refracted but totally reflected.

===================================

12a)
binding energy is the minimum energy that would be required to disassemble the nucleus of an atom into its component parts. These component parts are neutrons and protons, which are collectively called nucleons.

(12b) They have short wire length and high frequency.
-They are highly penetrating
-They travel in straight line
-They don’t require material medium for their propagation

==

6)
Given constant = 2.9×10^-3mk
Temperature = 57degreeC = (57+273)k = 330k
Using landamaxT = constant 
landamaxT330 = 2.9×10^-3
landamax = 2.9×10^-3/330
landamax = 8.788×10^-6m
The speed of electromagnetic wave, v = 3×10^8m/s
Using V = f landa
f = v/landa
=3×10^8/8.788×10^-6
=3.4×10^13Hz

5)
Range = u²Sin2tita/g
At maximum range 
Sin2tita = 1
2tita =sin^-1(1)
2tita = 90dgrees 
Tita = 90/2 = 45degree

Maximum height reached = u²sin²tita/2g
=u²(sin45)²/2g
=200²(sin45)²/2(10)
=40000(1/√2)2/20
=40000(1/2)/20
=20000/20
=1000metres.

12a) This is defined as the amount of energy that must be supplied to a nucleus to completely separate it’s nuclear particles (nucleons)

12b) 
i) They have short wavelength and high frequency. 
ii) They are highly penetrating. 
iii) They travel in straight lines. 
iv) They don’t require material medium for their propagation.

(4a)
An intrinsic semiconductor is an undoped semiconductor that is a pure semiconductor without any significant dopant species present.

(4b)
The P Type semiconductor is a type of semiconductor that carries a positive charge, while the N type semiconductor carries a negative charge .

===

12c) 
i)It is used in production of electricity. 
ii)It is used to study and detect charges in genetic engineering. 
iii)It is used in agriculture. 
iv)It is used in treatment of cancer. 

12di)
E = hf-hfo
but f = v/landa
E= v/landa.h – wo
Where wo = hfo = work function 
f= frequency 
landa = wavelength 
Hence 
hf = hfo – E
f = hfo – E/h
f = wo – E/h
Recall; that v = f landa
Therefore f = v/landa = 3×10^8/4.5×10-7
=3/4.5 × 10^8+7
=6.6×10^14Hz
f = 6.6×10^14Hz

12dii) 
E = hf
=6.6×10^-34 × 6.6×10^14Hz
=43.56×10^-20J

12diii) 
Energy of the photoelectron E = hf – vo
=Energy of incident electron – work function 
=4.356×10^-19J – 3.0×10^-19J
=1.356×10^-19J

===

10a)
Diffraction is the ability of waves to bend around obstacles in their path

(10bi)
Critical angle is the highest angle of incidence in a denser medium when angle of refraction in the less dense mediumis 90 degrees

(10bii)
Critical angle=90-44=46degrees
The refractive index of the glass is obtained as follows
The refractive index(n)=sini/sinr=sin46/sin90=0.7193/1
=0.719

(10ci)
fo=200Hz
f1=3v/4l =>closed pipe
f1=v/l=>open pipe
but 3fo=f1=>closed pipe
3*200=f1=>f1=600Hz
Also f1=2fo=>open pipe
2fo=600
fo=600/2=300Hz

(10cii)
v=330m/s
L=?
fo=200Hz
fo=v/4l
=>200=330/4l
800l=330
l=330/800
l=0.4124m

(10ciii)
fo=v/2l
fo=300Hz
v=330m/s
300=330/2l
l=330/600
l=0.55m

===================
9ai)
i)Nature of surface
ii)medium of transmission
9aii)
i)state or phase of the substance (i:e solid,or gas)
ii)temperature of the meduim

9b)
i)temperature
ii)specific heat capacity of the body

9c)
the statement means that the amount of heat energy required to change 1kg of liquid mercury to gaseous mecury without change in temperature is 2.72*10^5jkg^-1

9di)
Q=MCDSin
V^2/R t=MCDsin
(220)^2*4*60/35=M*4200*(100-28)
331885.7=302400m
m=331885.7/302400 =1.098kg
9dii)
V^2/R t = MLv
(220)^2*5*60/35=0.3*Lv
414857.14=0.3Lv
Lv=414857.14/0.3
Lv=1382857.13JKg^-1


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