## How to Get 2020 WAEC MATHEMATICS ESSAY AND OBJECTIVE Question Paper.

*Follow the steps below to get your waec mathematics*

*questions and answers 1 hours before your exam time.*

**Monday 17th August 2020**

General mathematics(core) 2(Essay) – 9:30am – 12:00noon (2hrs 30mins)

General mathematics(core) 2(objective) – 3:00pm – 4:30pm

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KEEP REFRESHING THIS PAGE

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**MATHS OBJ**

MATHS-OBJ

1-10:CBCDACDCCD

11-20:AADBDACBBC

21-30:BDDABDADAD

31-40:CDACCCCCDA

41-50:BBBCDCACDB

==Completed==

Given A={2,4,6,8,…}

B={3,6,9,12,…}

C={1,2,3,6}

U= {1,2,3,4,5,6,7,8,9,10}A’ = {1,3,5,7,9}

B’ = {1,2,4,5,7,8,10}

C’ = {4,5,7,8,9,10}

A’nB’nC’ = {5, 7}(1b)

Cost of each premiere ticket = $18.50

At bulk purchase, cost of each = $80.00/50 = $16.00Amount saved = $18.50 – $16.00

=$2.50=================================================

(2ai)

P = (rk/Q – ms)⅔

P^3/2 = rk/Q – ms

rk/Q = P^3/2 + ms

Q= rk/P^3/2 + ms

(2aii)

When P =3, m=15, s=0.2, k=4 and r=10

Q = rk/p^3/2 + ms = 10(4)/(3)^3/2 + (15)(0.2)

= 40/8.196 = 4.88(1dp)

(2b)

x + 2y/5 = x – 2y

Divide both sides by y

X/y + 2/5 = x/y – 2

Cross multiply

5(x/y) – 10 = x/y + 2

5(x/y) – x/y = 2 + 10

4x/y = 12

X/y = 3

X : y = 3 : 1

=================================================

(3a)

Draw the diagram

CBD = CDB(Base angles of an issoceles triangle)

BCD + CBD + CDB = 180°(sum of angles in a triangle)

2CDB + BCD = 180°

2CDB + 108° = 180°

2CDB = 180° – 108° =72°

CDB = 72/2 = 36°

BDE = 90°(angle in a semi-circle)

CDE = CDB + BDE

= 36° + 90°

= 126°

(3b)

(CosX)² – SinX/(SinX)²+ CosX

Using Pythagoras theorem, third side of triangle

y² = 1² + |3²

y² = 1 + 3 = 4

y = square root e = 2

Cos X = 1/2(adj/hyp)

Sin X = root 3/2(opp/hyp)

(CosX)² – SinX/(SinX)² + CosX

= (1/2)² – root3/2 / (root3/2)² + 1/2

= 1/4 – root3/2 / 3/4 + 1/2

= 1 – 2root3/4 / 3+2/4

= 1-2root3/5

====

(5a)

Prob(2) = no of 2s/Total outcomes

0.15 = m/32+m+25+40+28+45

0.15 = m/m + 170

m = 0.15m + 25.5

m – 0.15m = 25.5

0.85m = 25.5

m = 25.5/0.85 = 30

(5b)

Number of times dice was rolled = m + 170

= 30 + 70

= 200

(5c)

Prob(even number) = no of even numbers/Total outcome

= m+40+45/200

=30+40+45/200

=115/200

= 23/40 = 0.575

=====

(7a)

Total surface area = url + 2πr²

=πr(l + 2r)

Draw the diagram

From pythagoras theorem

Hyp² = Adj² + Opp²

L² = 14² + 48²

L² = 196 + 2304

L² = 2500

L = /2500 = 50m

=πr(L + 2r)

= 22/7 ×14(50 + 2(14))

= 44(50 + 28)

= 3432m²

Total surface area = 3432m²

~3430m²(to 3s.f)

(7b)

Five years ago,

Let Musa’s age = x

Let Sesay’s age = y

X – 5 = 2(Y – 5)

X – 5 = 2y – 10

X – 2y = 5 – 10

X – 2y = -5 ….. (1)

-X + y = 100 ….. (2)

-3y = -105

Subtracting eqn 2 from 1

-3y/3 = -105/-3

y = 35

Sesay’s present age = 35 years

======

(12a)

BCD=ABC=40°(alternate D)

DDE=2*BCD(<at centre = twice < at circle)

DDE = 2*40 = 80°

OD3=OED(base < of I sealed D ODE)

ODE + OED + DOE= 180°(sum of < is in D)

2ODE+DOE=180°

2ODE+80°=180

2ODE+180=180

2ODE+100°

ODE+100/2=50°

(12bi)

Digram

(12bii)

Area of parallelogram = absin

=5*7*sin125°

=35*sin55°

=35*0.8192

=28.67

=28.7cm²(1dp)

(12c)

Given x=1/2(1-√2)

2x²-2x=2[1/2(1-√2]²-2(1/2(1-√2)}

=2[1-2√2+2/4]-(1-√2)

=(3-2√2/2)-(1-√2)

=3-2√2-2+2√2/2=1/2

======

How to get the math obj

by Ogunnubi oluwaTosin on Aug 17, 2020 at

Hi

by Gabriel rotimi julius on Aug 16, 2020 at

Help me to waec anwer

by Aminu on Aug 16, 2020 at