## ATTENTION:- PLEASE AFTER SENDING YOUR CARD DO NOT THROW THEM AWAY UNTIL YOU RECEIVE A CONFIRMATION MESSAGE FROM US.

*2020 WAEC GCE ALTERNATIVE TO PRACTICAL ANSWERS VERIFIED EXPO*

==============================================

(1)
Tabulate
S/n ; 1|2|3|4|5
Xi/Cm; |6.50|6 00|5.50|5.00|4.50

Xi/cm; |32.50|30 00|27.50|25.00|22.50

Mg/I; |100.00|120.00|150.00|170.00|22000|

Xi^-¹/cm^-¹; |0.031|0.033|0.036|0.04|0.044|

Graph.
[img]https://i.imgur.com/EQ2hUAa.jpg[/img]

(1ix)
Slope S = DXi^-¹/cm^-¹/Δm/g = 0.044-0.031/220-100 =1.083*10^-⁴

(1x)
S=1.083*10^-⁴ =1/45(50+Mr)
50 + Mr = 1/45*1.083*10^-⁴
=205.13
Mr=205.13-50=155.13gcm

(1xi)
(i)I close the window to avoid air resistance during balancing of the meter rule
(ii)I took my reading at eye level to avoid error due to parallax

1bi)
•The first condition is that the net force on the object must be zero for the object to be stable
•If net force is zero, then net force along any direction is zero.

1bii)
(i) Magnitude of force applied.
(ii) Distance of line of action of the force from the axis of rotation.

==============================================

2avii.
Precautions taken are:
1. I ensured neat traces by using sharp pencil.
2. I ensured that the pins are vertically erect.
3. I avoided parallax error when reading the protractor.
4. I ensured that the pins are well spaced which is 4cm apart

==============================================

3a.( IX.)
2. Large current or voltage must not be passed into the meter because it might damage it.
3. The calorimeter must be properly lagged to prevent heat loss.

Choose any 3.

3b)
SPECIFIC HEAT CAPACITY: of a substance is defined as the quality of heat supplied or required to raise the temperature of a unit mass of 1kg through a unit rise in the temperature of 1kelvin.(K)

(3bi)
The specific heat of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. … The units for specific heat can either be joules per gram per degree (J/g°C) or calories per gram per degree (cal/g°C). This text will use J/g°C for specific heat.

3bii)

Pt=C¶

P x 12 ×60=(50-30) × 6300

P=175W

==============================================

SUBSCRIPTION PRICE LIST;

Direct SMS (You get the complete Answers Direct to your phone Via SMS) ===> N500 MTN CARD

WhatsApp (You get the complete Questions and Answers Direct to your phone Via WhatsApp) ===> N400 MTN CARD

Online Answers Page: (Here we send you the password to our Answers Page where the answers are posted online.) ===> N400 MTN CARD

NOTE:- Subscription Ends 1Hrs to each paper.

## 2020 WAEC GCE PHYSICS PRACTICAL Questions and Answers

WARNING: For more info/clarification, You can always reach us through Text Message (SMS) or WhatsApp chat.

WE DON’T TALK MUCH

Learn how to pay for what you need most. Be wise and try harder to pass

Always Subscribe To Avoid Being On Hot Seat.